一、题目

Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

For example,
"A man, a plan, a canal: Panama" is a palindrome.
"race a car" is not a palindrome.

Note:

Have you consider that the string might be empty? This is a good question to ask during an interview.

For the purpose of this problem, we define empty string as valid palindrome.

判断一个字符串是不是回文串。

二、解题思路

字符串的回文判断问题,由于字符串可随机访问,故逐个比较首尾字符是否相等最为便利,即常见的『两根指针』技法。

两步走:

  1. 找到最左边和最右边的第一个合法字符(字母或者字符)
  2. 一致转换为小写进行比较

三、解题代码

  1. public class Solution {
  2. public boolean isPalindrome(String s) {
  3. if (s == null || s.trim().isEmpty()) {
  4. return true;
  5. }
  6. int l = 0, r = s.length() - 1;
  7. while (l < r) {
  8. if(!Character.isLetterOrDigit(s.charAt(l))) {
  9. l++;
  10. continue;
  11. }
  12. if(!Character.isLetterOrDigit(s.charAt(r))) {
  13. r--;
  14. continue;
  15. }
  16. if (Character.toLowerCase(s.charAt(l)) == Character.toLowerCase(s.charAt(r))) {
  17. l++;
  18. r--;
  19. } else {
  20. return false;
  21. }
  22. }
  23. return true;
  24. }
  25. }