dayofyear

description

Syntax

INT DAYOFYEAR(DATETIME date)

获得日期中对应当年中的哪一天。

参数为Date或者Datetime类型

example

mysql> select dayofyear('2007-02-03 00:00:00');
+----------------------------------+
| dayofyear('2007-02-03 00:00:00') |
+----------------------------------+
|                               34 |
+----------------------------------+

keyword

DAYOFYEAR