6. 在Series上使用运算符

 In[48]: pd.options.display.max_rows = 6
 In[49]: 5 + 9    #  加法
Out[49]: 14

 In[50]: 4 ** 2   #  幂运算
Out[50]: 16

 In[51]: a = 10   #  赋值

 In[52]: 5 <= 9 #  小于等于
Out[52]: True

 In[53]: 'abcde' + 'fg' #  字符串拼接
Out[53]: 'abcdefg'

 In[54]: not (5 <= 9)  #  非运算符
Out[54]: False

 In[55]: 7 in [1, 2, 6]  #  in运算符
Out[55]: False

 In[56]: set([1,2,3]) & set([2,3,4])  #  求交集
Out[56]: {2, 3}

#  不支持列表和整数间的运算
 In[57]: [1, 2, 3] - 3 
---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-57-7ca967348b32> in <module>()
----> 1 [1, 2, 3] - 3
TypeError: unsupported operand type(s) for -: 'list' and 'int'

 In[58]: a = set([1,2,3])     
         a[0]                 #  集合不支持索引

准备

#  选取imdb_score这列
 In[59]: movie = pd.read_csv('data/movie.csv')
         imdb_score = movie['imdb_score']
         imdb_score
Out[59]: 0       7.9
         1       7.1
         2       6.8
             ... 
         4913    6.3
         4914    6.3
         4915    6.6
         Name: imdb_score, Length: 4916, dtype: float64

#  每列值加1
 In[60]: imdb_score + 1
Out[60]: 0       8.9
         1       8.1
         2       7.8
             ... 
         4913    7.3
         4914    7.3
         4915    7.6
         Name: imdb_score, Length: 4916, dtype: float64

#  每列值乘以2.5
 In[61]: imdb_score * 2.5
Out[61]: 0       19.75
         1       17.75
         2       17.00
             ...  
         4913    15.75
         4914    15.75
         4915    16.50
         Name: imdb_score, Length: 4916, dtype: float64

#  每列值除以7的余数
 In[62]: imdb_score // 7
Out[62]: 0       1.0
         1       1.0
         2       0.0
              ... 
         4913    0.0
         4914    0.0
         4915    0.0
         Name: imdb_score, Length: 4916, dtype: float64

#  判断是否大于7
 In[63]: imdb_score > 7
Out[63]: 0        True
         1        True
         2       False
               ...  
         4913    False
         4914    False
         4915    False
         Name: imdb_score, Length: 4916, dtype: bool

#  判断是否等于字符串
 In[64]: director = movie['director_name']
 In[65]: director == 'James Cameron'
Out[65]: 0        True
         1       False
         2       False
               ...  
         4913    False
         4914    False
         4915    False
         Name: director_name, Length: 4916, dtype: bool

更多

#  利用通用函数实现加法
 In[66]: imdb_score.add(1)              #  imdb_score + 1
Out[66]: 0       8.9
         1       8.1
         2       7.8
              ... 
         4913    7.3
         4914    7.3
         4915    7.6
Name: imdb_score, Length: 4916, dtype: float64

#  利用通用函数实现乘法
 In[67]: imdb_score.mul(2.5)            #  imdb_score * 2.5
Out[67]: 0       19.75
         1       17.75
         2       17.00
               ...  
         4913    15.75
         4914    15.75
         4915    16.50
         Name: imdb_score, Length: 4916, dtype: float64

#  利用通用函数实现底除
 In[68]: imdb_score.floordiv(7)         #  imdb_score // 7
Out[68]: 0       1.0
         1       1.0
         2       0.0
              ... 
         4913    0.0
         4914    0.0
         4915    0.0
         Name: imdb_score, Length: 4916, dtype: float64

#  利用通用函数实现大于
 In[69]: imdb_score.gt(7)               #  imdb_score > 7
Out[69]: 0        True
         1        True
         2       False
               ...  
        4913    False
        4914    False
        4915    False
        Name: imdb_score, Length: 4916, dtype: bool

#  利用通用函数实现等于
 In[70]: director.eq('James Cameron')   #  director == 'James Cameron'
Out[70]: 0        True
         1       False
         2       False
               ...  
         4913    False
         4914    False
         4915    False
         Name: director_name, Length: 4916, dtype: bool

#  利用通用函数实现取模
 In[71]: imdb_score.astype(int).mod(5)
Out[71]: 0       2
         1       2
         2       1
              ..
         4913    1
         4914    1
         4915    1
         Name: imdb_score, Length: 4916, dtype: int64

#  a是int对象
 In[72]: a = type(1)
 In[73]: type(a)
Out[73]: type

#  a是pandas.core.series.Series对象
 In[74]: a = type(imdb_score)
 In[75]: a([1,2,3])
Out[75]: 0    1
         1    2
         2    3
         dtype: int64