ImageChops (“Channel Operations”) Module

The ImageChops module contains a number of arithmetical imageoperations, called channel operations (“chops”). These can be used for variouspurposes, including special effects, image compositions, algorithmic painting,and more.

For more pre-made operations, see ImageOps.

At this time, most channel operations are only implemented for 8-bit images(e.g. “L” and “RGB”).

Functions

Most channel operations take one or two image arguments and returns a newimage. Unless otherwise noted, the result of a channel operation is alwaysclipped to the range 0 to MAX (which is 255 for all modes supported by theoperations in this module).

  • PIL.ImageChops.add(image1, image2, scale=1.0, offset=0)[源代码]
  • Adds two images, dividing the result by scale and adding theoffset. If omitted, scale defaults to 1.0, and offset to 0.0.At least one of the images must have mode “1”.
  1. out = ((image1 + image2) / scale + offset)

返回类型:Image

  • PIL.ImageChops.addmodulo(_image1, image2)[源代码]
  • Add two images, without clipping the result. At least one of the imagesmust have mode “1”.
  1. out = ((image1 + image2) % MAX)

返回类型:Image

  • PIL.ImageChops.blend(image1, image2, alpha)[源代码]
  • Blend images using constant transparency weight. Alias forPIL.Image.Image.blend().

返回类型:Image

  • PIL.ImageChops.composite(image1, image2, mask)[源代码]
  • Create composite using transparency mask. Alias forPIL.Image.Image.composite().

返回类型:Image

  • PIL.ImageChops.constant(image, value)[源代码]
  • Fill a channel with a given grey level.

返回类型:Image

  • PIL.ImageChops.darker(image1, image2)[源代码]
  • Compares the two images, pixel by pixel, and returns a new image containingthe darker values. At least one of the images must have mode “1”.
  1. out = min(image1, image2)

返回类型:Image

  • PIL.ImageChops.difference(image1, image2)[源代码]
  • Returns the absolute value of the pixel-by-pixel difference between the twoimages. At least one of the images must have mode “1”.
  1. out = abs(image1 - image2)

返回类型:Image

返回类型:Image

  • PIL.ImageChops.invert(image)[源代码]
  • Invert an image (channel).
  1. out = MAX - image

返回类型:Image

  • PIL.ImageChops.lighter(image1, image2)[源代码]
  • Compares the two images, pixel by pixel, and returns a new image containingthe lighter values. At least one of the images must have mode “1”.
  1. out = max(image1, image2)

返回类型:Image

  • PIL.ImageChops.logicaland(_image1, image2)[源代码]
  • Logical AND between two images. At least one of the images must havemode “1”.
  1. out = ((image1 and image2) % MAX)

返回类型:Image

  • PIL.ImageChops.logicalor(_image1, image2)[源代码]
  • Logical OR between two images. At least one of the images must havemode “1”.
  1. out = ((image1 or image2) % MAX)

返回类型:Image

  • PIL.ImageChops.logicalxor(_image1, image2)[源代码]
  • Logical XOR between two images. At least one of the images must havemode “1”.
  1. out = ((bool(image1) != bool(image2)) % MAX)

返回类型:Image

  • PIL.ImageChops.multiply(image1, image2)[源代码]
  • Superimposes two images on top of each other.

If you multiply an image with a solid black image, the result is black. Ifyou multiply with a solid white image, the image is unaffected. At leastone of the images must have mode “1”.

  1. out = image1 * image2 / MAX

返回类型:Image

  • PIL.ImageChops.offset(image, xoffset, yoffset=None)
  • Returns a copy of the image where data has been offset by the givendistances. Data wraps around the edges. If yoffset is omitted, itis assumed to be equal to xoffset.
  • PIL.ImageChops.screen(image1, image2)[源代码]
  • Superimposes two inverted images on top of each other. At least one of theimages must have mode “1”.
  1. out = MAX - ((MAX - image1) * (MAX - image2) / MAX)

返回类型:Image

  • PIL.ImageChops.subtract(image1, image2, scale=1.0, offset=0)[源代码]
  • Subtracts two images, dividing the result by scale and adding the offset.If omitted, scale defaults to 1.0, and offset to 0.0. At least one of theimages must have mode “1”.
  1. out = ((image1 - image2) / scale + offset)

返回类型:Image

  • PIL.ImageChops.subtractmodulo(_image1, image2)[源代码]
  • Subtract two images, without clipping the result. At least one of theimages must have mode “1”.
  1. out = ((image1 - image2) % MAX)

返回类型:Image